Suppose 3 bulbs are selected at random from a lot. Each bulb is tested and classified as defective (D) or non – defective(N). Write the sample space of this experiment.
Let D denote the event the bulb is defective, N denote the event the bulb is non-defective
Total Number of sample space=(2×2×2)=8
We define the possible outcomes by an ordered set (x, y, z)
where
x denotes the event first bulb is selected
y denotes the event second bulb is selected
z denotes the event third bulb is selected
Sample space S={(D,D,D), (D,D,N), (D,N,D), (N,D,D), (D,N,N), (N,D,N), (N,N,D), (N,N,N)}