Given: Cartesian product A × A having 9 elements among which are found (–1, 0) and (0,1).

Number of elements in (A× B) = (Number of elements in set A) × (Number of elements in B)

⇒ n(A × A) = n(A) × n(A)

⇒ n(A × A) = 9 (given)

⇒ n(A) × n(A) = 9

⇒ n(A) = 3

By definition A × A = {(a, a): a Є A}.

Therefore, -1, 0 and 1 are the elements of set A.

Because, n(A) = 3 therefore, A = {-1, 0, 1}.

Hence the remaining elements of set (A × A) are:

(-1,-1), (-1,1), (0,0), (0, -1), (1,1), (1, -1) and (1, 0).