It is given in the question that,

3(x – 1) ≤ 2 (x – 3)

3x – 3 ≤ 2x – 6

Adding 3 to both the sides,

3x – 3+ 3 ≤ 2x – 6+ 3

3x ≤ 2x – 3

Subtracting 2x from both the sides,

3x – 2x ≤ 2x – 3 – 2x
x ≤ -3
∴ The solutions of the given inequality are defined by all the real numbers less than or equal to -3.

Thus, (-∞, -3] is the required solution set.