Solve the inequalities in Exercises 5 to 16 for real x:

37 – (3x + 5) ≥ 9x – 8 (x – 3)

We have,

37 - (3x + 5) ≥ 9x - 8 (x - 3)


= 37 - 3x – 5 ≥ 9x - 8x + 24


= 32 - 3x ≥ x + 24


= 32 - 24 ≥ x + 3x


= 8 ≥ 4x


= 2 ≥ x


All the real numbers of x which are less than or equal to 2 are the solutions of the given inequality


Hence, will be the solution for the given inequality


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