Let us assume x be the smaller of the two consecutive odd positive integers

∴ Other integer = x + 2

It is also given in the question that, both the integers are smaller than 10

∴ x + 2 < 10

x < 8 (i)

Also, it is given in the question that sum off two integers is more than 11

∴ x + (x + 2) > 11

2x + 2 > 11

x > 4.5 (ii)

Thus, from (i) and (ii) we have x is an odd integer and it can take values 5 and 7

Hence, possible pairs are (5, 7) and (7, 9)