Find (x + 1)6 + (x – 1)6. Hence or otherwise evaluate 
.
We know that-
Hence
Thus, 
Replacing b with -b
Now,
Putting a = x & b = 1 in 
, we get-
putting x = √2
Hence, 
15
Find (x + 1)6 + (x – 1)6. Hence or otherwise evaluate .
We know that-
Hence
Thus,
Replacing b with -b
Now,
Putting a = x & b = 1 in , we get-
putting x = √2
Hence,