Find the coefficient of

x5 in (x + 3)8

The general term Tr+1 in the binomial expansion is given by Tr+1 = nCr an-r br


Here x5 is the Tr+1 term so


a= x, b = 3 and n =8


Tr+1 = 8Cr x8-r 3r……………1


For finding out x5


We equate x5= x8-r


r= 3


Putting value of r in 1 we get


T3+1 = 8C3 x8-3 33



= 1512 x5


Hence the coefficient of x5= 1512


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