In the expansion of (1 + a)m+n, prove that coefficients of am and an are equal.

The general term Tr+1 in the binomial expansion is given by Tr+1 = nCr an-r br

Here n= m+n , a = 1 and b= a


Putting the values in the general form


Tr+1 = m+nCr 1m+n-r ar


= m+nCr ar………….1


The coefficient of am is & the coefficient of an is


ar = am an = ar


r=m n =r


Putting r = m in 1 & putting r= n in 1


Tm+1= m+nCm1m+n-m amTn+1 = m+nCn1m+n-n an


&


&


The coefficient of am and an are same i.e.;


Hence proved.


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