Find the equation of the plane passing through (a, b, c) and parallel to the plane .
The equation of a plane passing through (x1,y1,z1) and perpendicular to a line with direction ratios A, B, C is
A(x - x1) + B(y - y1) + C(z - z1) = 0
The plane passes through (a,b,c)
So, x1 = a, y1 = b, z1 = c
Since both planes are parallel to each other, their normal will be parallel
∴ Direction ratios of normal
= Direction ratios of normal of
Direction ratios of normal = (1,1,1)
∴ A = 1, B =1, C = 1
Thus,
Equation of plane in cartesian form is
A(x - x1) + B(y - y1) + C(z - z1) = 0
⇒ 1(x - a) + 1(y - b) + 1(z - c) = 0
⇒ x + y + z - (a + b + c) = 0
Thus, x + y + z = a + b + c is the required equation of plane.