Given , what is the value of ?
Given,
tan θ = 1/√5
In ∆ ABC,
AC2 = AB2 + BC2
AC2 = 12 + (√5)2
AC2 = 1 + 5 = 6
AC = √6
We have,
cosec θ = AC/AB = √6/1
sec θ = AC/BC = √6/√5
Now,