If
, rite the value of 
Given,
cot θ = 1/√3
In ∆ABC,
AC2 = AB2 + BC2
AC2 = (√3)2 + 12
AC2 = 3 + 1 = 4
AC= 2
We get;
cos θ = BC/AC = 1/2
sin θ = AB/AC = √3/2
Now,
9
If, rite the value of
Given,
cot θ = 1/√3
In ∆ABC,
AC2 = AB2 + BC2
AC2 = (√3)2 + 12
AC2 = 3 + 1 = 4
AC= 2
We get;
cos θ = BC/AC = 1/2
sin θ = AB/AC = √3/2
Now,