If 16 cot x = 12, then equals
Given,
16 cot x = 12
So,
cot x = 12/16
cot x = 3/4
In ∆ ABC,
AC2 = AB2 + BC2
AC2 = (3)2 + (4)2
AC2 = 9 + 16 = 25
AC = 5
Therefore,
sin x = AB/AC = 4/5
cos x = BC/AC = 3/5
Now,