Given, tan θ = 1/√7 In ∆ ABC, AC 2 = AB 2 + BC 2 AC 2 = (1) 2 + (√7) 2 AC 2 = 8 AC = 2√2 Therefore, Now,

If , then =

Given,

tan θ = 1/√7

In ∆ ABC,

AC² = AB² + BC²

AC² = (1)² + (√7)²

AC² = 8

AC = 2√2

Therefore,

Now,