If tan θ = 3/4, then cos2 θ – sin2 θ =
Given,
tan θ = 3/4
In ∆ ABC,
AC2 = AB2 + BC2
AC2 = (3)2 + (4)2
AC2 = 9 + 16 = 25
AC = 5
Therefore,
sin θ = p/h = 3/5 and
cos θ = b/h = 4/5
Now putting these values in the given equation we get,
cos2 θ – sin2 θ =