If θ and 2θ – 45° are acute angles such that sin θ = cos (2θ – 45°), then tan θ is equal to
Given,
θ and 2θ – 45° are acute angle,
sin θ = cos (2θ – 45)………….. (i)
[∵ cos (90 – θ) = sin θ]
Putting these value in equation (i),
Cos (90 – θ) = cos (2θ – 45°)
90 - θ = 2 θ – 45°
90 + 45 = 3 θ
3 θ = 135
θ = 135/3 = 45
tan θ = tan 45° = 1