If θ and 2θ – 45° are acute angles such that sin θ = cos (2θ – 45°), then tan θ is equal to

Given,


θ and 2θ – 45° are acute angle,


sin θ = cos (2θ – 45)………….. (i)


[ cos (90 – θ) = sin θ]


Putting these value in equation (i),


Cos (90 – θ) = cos (2θ – 45°)


90 - θ = 2 θ – 45°


90 + 45 = 3 θ


3 θ = 135


θ = 135/3 = 45


tan θ = tan 45° = 1

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