In Fig. 5.48, AD = 4 cm BD = 3 cm and CB = 12 cm, find cot θ.
Given,
AD = 4cm
BD = 3 cm
CB = 12 cm
In ∆ABC,
AB2 = AD2 + BD2
AB2 = 42 + 32
AB = √16 + 9 = 5 cm
Then,
cot θ = CB/AB = 12/5