If sec θ + tanθ = x, write the value of sec θ − tan θ in terms of x.
Given: sec θ + tan θ = x ……………(i)
To find: sec θ – tan θ
We know that 1 + tan2 θ = sec2 θ
⇒ 1 = sec2 θ – tan2 θ
Now, ∵ a2 – b2 = (a – b) (a + b)
⇒ 1 = sec2 θ – tan2 θ = (sec θ – tan θ) (sec θ + tan θ)
⇒ From (i), we have
1 = (sec θ – tan θ) x