To find: Consider Rationalizing the above fraction by (1 – cos θ), [ ∵ (a – b) (a + b) = a 2 – b 2 ] ∵ sin 2 θ + cos 2 θ = 1 ⇒ sin 2 θ = 1 – cos 2 θ

is equal to

To find:

Consider

Rationalizing the above fraction by (1 – cos θ),

[∵ (a – b) (a + b) = a² – b²]

∵ sin² θ + cos² θ = 1

⇒ sin² θ = 1 – cos² θ