The value of (1 + cot θ cosec θ) (1 + tan θ + sec θ) is

To find: (1 + cot θ cosec θ) (1 + tan θ + sec θ)

Consider (1 + cot θ cosec θ) (1 + tan θ + sec θ)





[ (a – b) (a + b) = a2 – b2]



[ sin2 θ + cos2 θ = 1]


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