(cosec θ − sin θ) (sec θ − cos θ) (tan θ + cot θ) is equal
To find: (cosec θ – sin θ) (sec θ – cos θ) (tan θ + cot θ)
∵
∴ (cosec θ – sin θ) (sec θ – cos θ) (tan θ + cot θ)
Now, as sin2 θ + cos 2 θ = 1
⇒ sin2 θ = 1 – cos2 θ
And cos2 θ = 1 – sin2 θ
⇒ (cosec θ – sin θ) (sec θ – cos θ) (tan θ + cot θ)