A hickey ball of mass 200 g travelling at 10 ms -1 is struck by a hockey stick so as to return it along its original path with a velocity of 5 ms -1 . Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Question

Philoid · Accepted Answer

Firstly, we will calculate the initial momentum:

Given,

Mass of hockey ball, m₁ = 200 g

= kg

= 0.2 kg

Initial velocity, v₁ = 10 m/s

So,

Initial momentum = m₁ × v₁

= 0.1 × 10

= 2 kg m/s (i)

Now, we will calculate the final momentum:

Given,

Mass of hockey ball, m₂ = 200 g

= 0.2 kg

Final velocity, v₂= - 5 m/s

So,

Final momentum = m₂ × v₂

= 0.2 × (-5)

= - 1 kg m/s (ii)

Now,

Change in momentum = Final momentum – Initial momentum

= -1 -2

= - 3 kg m/s

Therefore, the change in momentum of the hockey ball is 3 kg m/s.

A hickey ball of mass 200 g travelling at 10 ms-1 is struck by a hockey stick so as to return it along its original path with a velocity of 5 ms-1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

A hickey ball of mass 200 g travelling at 10 ms^-1 is struck by a hockey stick so as to return it along its original path with a velocity of 5 ms^-1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.