The value of is
In given equation let x =
So, x = √(6 + x)
Now squaring both side
x2 = 6 + x
X2 – x – 6 = 0
X2 – 3x + 2x – 6 = 0
x(x – 3) + 2(x – 3) = 0
(x – 3) (x + 2) = 0
x = 3 or – 2
x cannot be equal to – 2 as root can never be negative.
x = 3