If x = 1 is a common root of the equations ax2 + ax + 3 = 0 and x2 + x + b = 0, then ab =
Since x = 1 is root of equations, it will satisfy both the equations.
Putting x = 1 in ax2 + ax + 3 = 0
1a + a + 3 = 0
2a + 3 = 0
A = – 3/2
Putting x = 1 in x2 + x + b = 0
1 + 1 + b = 0
b = – 2
ab = 3