If the sum of the roots of the equation x2 – (k + 6)x + 2 (2k – 1) = 0 is equal to half of their product, then k =
In the given equation x2 – (k + 6)x + 2 (2k – 1) = 0
a = 1, b = – (k + 6), c = 2 (2k – 1)
Sum of the roots = 1/2 (product of roots) (given)
K + 6 = 2k – 1
K = 7