If the sum of the roots of the equation x2 – (k + 6)x + 2 (2k – 1) = 0 is equal to half of their product, then k =

In the given equation x2 – (k + 6)x + 2 (2k – 1) = 0

a = 1, b = – (k + 6), c = 2 (2k – 1)


Sum of the roots = 1/2 (product of roots) (given)


K + 6 = 2k – 1


K = 7

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