In Fig. 10.76, CP and CQ are tangents from an external point C to a circle with centre O. AB is another tangent which touches the circle at R. If CP = 11 cm and BR = 4 cm, find the length of BC.
[Hint: We have, CP = 11 cm
Now, BR = BQ [Tangents drawn from B)
BQ = 4 cm
BC = CQ - BQ = (11 - 4)cm = 7 cm
Given:
BR = 4 cm
CP = 11 cm
Property: If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency on circle) are equal.
Using the above property,
BR = BQ = 4 cm (tangent from B)
And,
CP = CQ = 11 cm (tangent from C)
Now,
BC = CQ – BQ
= 11 cm – 4 cm
=7 cm
Hence, BC = 7 cm