In Fig. 10.76, CP and CQ are tangents from an external point C to a circle with centre O. AB is another tangent which touches the circle at R. If CP = 11 cm and BR = 4 cm, find the length of BC.


[Hint: We have, CP = 11 cm


CP = CQ = CQ = 11 cm


Now, BR = BQ [Tangents drawn from B)


BQ = 4 cm


BC = CQ - BQ = (11 - 4)cm = 7 cm

Given:


BR = 4 cm


CP = 11 cm


Property: If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency on circle) are equal.


Using the above property,


BR = BQ = 4 cm (tangent from B)


And,


CP = CQ = 11 cm (tangent from C)


Now,


BC = CQ – BQ


= 11 cm – 4 cm


=7 cm


Hence, BC = 7 cm


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