A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q such that OQ = 12 cm. Length PQ is cm
Given:
OQ = 12 cm
Property: The tangent at a point on a circle is at right angles to the radius obtained by joining center and the point of tangency.
By above property, ∆POQ is right-angled at ∠OPQ.
Therefore,
By Pythagoras Theorem in ∆POQ,
OP2 + PQ2 =OQ2
⇒ PQ2 = OQ2 – OP2
⇒ PQ= √( OQ2 – OP2)
⇒ PQ= √(122 – 52)
⇒ PQ= √(144 – 25)
⇒ PQ = √119 cm
Hence, PQ = √119 cm