A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q such that OQ = 12 cm. Length PQ is cm

Given:


OQ = 12 cm



Property: The tangent at a point on a circle is at right angles to the radius obtained by joining center and the point of tangency.


By above property, ∆POQ is right-angled at OPQ.


Therefore,


By Pythagoras Theorem in ∆POQ,


OP2 + PQ2 =OQ2


PQ2 = OQ2 – OP2


PQ= √( OQ2 – OP2)


PQ= √(122 – 52)


PQ= √(144 – 25)


PQ = 119 cm


Hence, PQ = √119 cm

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