If PT is tangent drawn from a point P to a circle touching it at T and O is the centre of the circle, then OPT + POT =


Property 1: The tangent at a point on a circle is at right angles to the radius obtained by joining center and the point of tangency.


Property 2: Sum of all angles of a triangle = 180°


By property 1, ∆PTO is right-angled at OTP (i.e., OTP = 90°).


By property 2,


OTP + POT + TPO = 180°


90° + POT + TPO = 180°


POT + TPO = 180° - 90°


POT + TPO = 90°


Hence, POT + TPO = 90°

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