The height of a tower is 10 m. What is the length of its shadow when Sun’s altitude is 45°?
Let BC be the height of tower which is 10m
Sun`s altitude is 45°
Let AB would be the shadow of the tower x meters
∴ tan 45° = BC /AB (tan θ = perdendicular/base)
⇒ 1= 10/x
x= 10m