From a point on the ground, 20 m away from the foot of a vertical tower, the angle of elevation of the top of the tower is 60°, what is the height of the tower?
Let the height of the tower be AC = x m
Distance from the foot of the vertical tower = 20m
tan 60° = AC/ BC
√3 = x / 20 ( tan 60° = √3)
x = 20√3