If the angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complimentary, find the height of the tower.
Let the height of the tower be h meters
Given, the angles of elevation of the top of a tower from two points are complimentary
∴ ∠ACB = θ and ∠ADB = 90° - θ
In Δ ABC
tan θ = 4 / h
h = 4tan θ…………1
In ΔABD
tan (90° - θ) =
h = 9 (cot θ) ………………..( tan (90° - θ) = cot θ ) 2
cot θ = h/9
cot θ =
1/tan θ =
9 = 4 tan2θ
tan θ = 3/2
Height of tower (h)= 4 × 3/2………..putting value of tan θ in 1
= 6m