If the angle of elevation of a tower from a distance of 100 meters from its foot is 60°, then the height of the tower is
Here, angle of elevation = 60°
Distance between the foot of tower and the shadow = 100m
Let height of the tower be h meters
Angle of elevation = tan θ =
tan 60° =
√3 × 100 = h
Height of tower = 100 √3 m