From the top of a cliff 25 m high the angle of elevation of a tower is found to be equal to the angle of depression of the foot of the tower. The height of the tower is
Here AB = 25 m is cliff and CE = (25 + x) m is tower
In Δ ADE
tan θ = 
…………….1
In Δ ABC
tan θ = 
…………….. 2
From 1 and 2
x =25 m
Total height of tower is 25 + x = 25 +25 = 50 m
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