A tower subtends an angle of 30° at a point on the same level as its foot. At a second point h metres above the first, the depression of the foot of the tower is 60°. The height of the tower is
Let the AB be the height be the tower
Let D be the point where the tower subtends angle of 30°
Let C be the point where such that CD = h meters. From C the angle of depression subtended at the foot of the tower is 60°
In Δ CDB
tan 60° =
BD = h cot 60°
BD = …………….1
In Δ ADB
tan 30° = AB/ BD
= AB / BD
AB = ×
AB = m