The length of the shadow of a tower standing on level ground is found to be 2x metres longer when the sun’s elevation is 30° than when it was 45°. The height of the tower in metres is


In Δ DBC


tan 45° = h /y


h = y ( tan 45° = 1)……….1


In ΔACD


tan 30° =


=


√3 h = 2x + h (from 1)


2x= (√3- 1) h
h =


h = (√3 +1)x meter

17