The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is
Here AB is the tower of 150m which forms the angel of depression = 30° from the top
Hence the angle of elevation from the car is 90° - 30° = 60°
In Δ ABC
tan 60° =
BC =
BC = 50 √3 m