If three coins are tossed simultaneously, then the probability of getting at least two heads, is

Total numbers of elementary events are: 2 x 2 x 2 = 8

Let E be the event of getting at least two heads


Favorable outcomes are: THH, HHT, HHH, HTH


Numbers of favorable outcomes are: 4


P (at least two heads) = P (E) = 4/8 = 1/2

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