If a two digit number is chosen at random, then the probability that the number chosen is a multiple of 3, is
Total numbers of elementary event are: 90
Let E be the event of choosing a multiple of 3
Favorable outcomes are: 3× 4 =12 , 3×5= 15, 3×6= 18, 3×7= 21,….. 3×33= 99
Numbers of favorable outcomes are= 30
P( multiple of 3) = P (E) = 30/90 = 1/3