Two different coins are tossed simultaneously. The probability of getting at least one head is

Total numbers of elementary events are 2×2 =4

Let E be the event of at least one head


Favorable events are: having one head or both the heads. The possibility with all tails is not considerable.


P (both tails) = 1/4


P (having at least one head) = P (E) = 1 – P (both tails) = 1 – 1/4 = 3/4

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