Two different coins are tossed simultaneously. The probability of getting at least one head is
Total numbers of elementary events are 2×2 =4
Let E be the event of at least one head
Favorable events are: having one head or both the heads. The possibility with all tails is not considerable.
P (both tails) = 1/4
P (having at least one head) = P (E) = 1 – P (both tails) = 1 – 1/4 = 3/4