Write the number of solutions of the following pair of linear equations:

x + 3y– 4 = 0


2x + 6y = 7

Given:

Equation 1: x + 3y = 4 Equation 2: 2x + 6y = 7


Both the equations are in the form of :


a1x + b1y = c1 & a2x + b2y = c2 where


a1 & a2 are the coefficients of x


b1 & b2 are the coefficients of y


c1 & c2 are the constants


According to the problem:


a1 = 1


a2 = 2


b1 = 3


b2 = 6


c1 = 4


c2 = 7


Comparing the ratios of the coefficients we see:


…(i)


…(ii)


…(iii)


On seeing equation (i), (ii) and (iii) we find



Conclusion: The system of linear equations has no solutions.


The given system of linear equations will have no solution for all values of x and y


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