The value of k for which the system of equations

kx – y = 2


6x – 2y = 3


has a unique solution, is

Given:

Equation 1: kx – y = 2


Equation 2: 6x – 2y = 3


Both the equations are in the form of :


a1x + b1y = c1 & a2x + b2y = c2 where


a1 & a2 are the coefficients of x


b1 & b2 are the coefficients of y


c1 & c2 are the constants


For the system of linear equations to have unique solution we must have


………(i)


According to the problem:


a1 = k


a2 = 6


b1 = – 1


b2 = – 2


c1 = 2


c2 = 3


Putting the above values in equation (i) we get


k ≠ k ≠ 3


The value of k for which the system of equations has unique solution is k≠3

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