The value of k for which the system of equations
x + 2y = 5
3x + ky + 15 = 0
has no solution is
Given:
Equation 1: x + 2y = 5
Equation 2: 3x + ky = – 15
Both the equations are in the form of :
a1x + b1y = c1 & a2x + b2y = c2 where
a1 & a2 are the coefficients of x
b1 & b2 are the coefficients of y
c1 & c2 are the constants
For the system of linear equations to have no solutions we must have
………(i)
According to the problem:
a1 = 1
a2 = 3
b1 = 2
b2 = k
c1 = 5
c2 = – 15
Putting the above values in equation (i) and solving we get: