If the system of equations kx – 5y = 2, 6x + 2y = 7 has no solution, then k =

Given:

Equation 1: kx – 5y = 2


Equation 2: 6x + 2y = 7


Both the equations are in the form of :


a1x + b1y = c1 & a2x + b2y = c2 where


a1 & a2 are the coefficients of x


b1 & b2 are the coefficients of y


c1 & c2 are the constants


For the system of linear equations to have no solutions we must have


………(i)


According to the problem:


a1 = k


a2 = 6


b1 = – 5


b2 = 2


c1 = 2


c2 = 7


Putting the above values in equation (i) and solving we get:



k k = – 15


Also we find


The value of k for which the system of equations has no solution is k = – 15

15