If α, β are the zeros of the polynomial 2y2 + 7y + 5, write the value of α + β + αβ.

Given,


Polynomial 2y2 + 7y + 5


Zeroes = a, 13


Here a = 2


b = 7


c = 5


Lets take α and β are two zero,


So sum of the zeroes will be,


α + β = – b/a = – 7/2


Product of the zeroes = α. β = c/a = 5/2


Now put the values,


α + β + αβ = (α + β) αβ


= – 7/2 + 5/2 = – 2/2 = – 1


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