If α, β are the zeros of the polynomial f (x) = x2 + x + 1, then =

Given,


f(x) = x2 + x + 1


α = a


β = b


c = c


α + β = – b/a


= – 1/1


= – 1 …….. Equ.(i)


αβ = c/a = 1 ….. Equ.(ii)


Dividing (i) from (ii)


We get,


– 1/1 = – 1


So,


1/α + 1/β = – 1

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