If α, β are the zeros of the polynomial f (x) = x2 + x + 1, then 
=
Given,
f(x) = x2 + x + 1
α = a
β = b
c = c
α + β = – b/a
= – 1/1
= – 1 …….. Equ.(i)
αβ = c/a = 1 ….. Equ.(ii)
Dividing (i) from (ii)
We get,
– 1/1 = – 1
So,
1/α + 1/β = – 1
1
If α, β are the zeros of the polynomial f (x) = x2 + x + 1, then =
Given,
f(x) = x2 + x + 1
α = a
β = b
c = c
α + β = – b/a
= – 1/1
= – 1 …….. Equ.(i)
αβ = c/a = 1 ….. Equ.(ii)
Dividing (i) from (ii)
We get,
– 1/1 = – 1
So,
1/α + 1/β = – 1