If α, β are the zeros of the polynomial p(x) = 4x2 + 3x + 7, then =

Given,


p(x) = 4x2 + 3x + 7


α + β = – b/a


= – 3x/4x2 = – 3/4x ………. (i)


αβ = c/a


= 7/4x2 …………. (ii)


Dividing (i) from (ii),


We get,




So,


1/α + 1/β = – 3/7

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