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If α, β are the zeros of the polynomial p(x) = 4x2 + 3x + 7, then =
Given,
p(x) = 4x2 + 3x + 7
α + β = – b/a
= – 3x/4x2 = – 3/4x ………. (i)
αβ = c/a
= 7/4x2 …………. (ii)
Dividing (i) from (ii),
We get,
So,
1/α + 1/β = – 3/7