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If the sum of the zeros of the polynomial f(x) = 2x3 – 3kx2 + 4x – 5 is 6, then the value of k is
Given,
f(x) = 2x3 – 3kx2 + 4x – 5
Sum of the zeros of the polynomial = 6
Let x, y and z be the zeroes than,
x + y + z = 6……Equation (i)
So,
x + y + z = – b/a
= – ( – 3k)/2
From Eq. (i) we get,
3k/2 = 6
k/2 = 6/3
k = 2×2 = 4