If α and β are the zeros of the polynomial f(x) = x2 + px + q, then a polynomial having 
and 
is its zeros is
Given,
f(x) = x2 + px + q
α + β = – p
αβ = q
1/α + 1/β = – p/q
x2 + p/q x + 1/q
So here we get,
g(x) = qx2 + px + 1
5
If α and β are the zeros of the polynomial f(x) = x2 + px + q, then a polynomial having and is its zeros is
Given,
f(x) = x2 + px + q
α + β = – p
αβ = q
1/α + 1/β = – p/q
x2 + p/q x + 1/q
So here we get,
g(x) = qx2 + px + 1