If α, β are the zeros of polynomial f(x) = x2 – p (x + 1) – c, then (α + 1) (β + 1) =
Given,
f(x) = x2 – p (x + 1) – c
α and β are the zeros
So,
f(x) = x2 – p (x + 1) – c
= x2 – px – (p + c)
As
(α + 1)(β + 1) = αβ + α + β + 1
= – p – c + p + 1
= 1 – c