If the product of two zeros of the polynomial f (x) = 2xZ^{3} + 6x^{2} – 4x + 9 is 3, then its third zero is

Given;

f(x) = 2x^{3} + 6x^{2} – 4x + 9

Product of the two zeros = 3

a = 2,

b = 6

c = – 4

d = 9

Let the zeros of f(x) be p, q, r

Product of the zeroes = – d/a

p×q×r = – 9/2

3r = – 9/2 … (given p×q = 3)

r = – 3/2

Hence,

Third zero = – 3/2

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