In Q. No. 14, c =

Given;


f(x) = ax3 + bx – c is divisible by g(x) = x2 + bx + c


Now by division Method first we have to calculate the value of ab,



As f(x) is divisible by g(x), then remainder must be 0,


i.e.


(ab2 – ac + b)x + c(ab – 1) = 0


(ab2 – ac + b)x = 0 and c(ab – 1) = 0


ab2 – ab + b = 0 ( x 0) and ab 1 = 0 ( c 0)


ab – 1 = 0


ab = 1


Now take;


ab2 – ac + b = 0


(ab)b – ac + b = 0


Using ab = 1 we get;


2b – ac = 0


c = 2b/a = 2b2/ab


As ab = 1


So we get;


c = 2b2

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